I'm aware that I can use sed or even cut to solve this. I'm pretty new to awk so I'm trying to focus on learning how to solve the problem using it. There are a number of patterns that match more than one character. You will have to remove those if your input contains more than just the addresses.I'm attempting to write a bash function that gets the UUID of a VirtualBox VM. Note however that some of the expressions are used to match only the IP address and therefore contain beginning- ( ^) and end-of-line ( $) characters. egrep 'pattern1pattern2' fileNameorfilePath Another option is to add multiple separate patterns to the grep command. grep -E 'pattern1pattern2' fileNameorfilePath The deprecated version of extended grep is egrep. This option treats the pattern you used as an extended regular expression. My file structure is: rose (good)ook daisy ()no lilly (bad)fine sunflower ()nice I need output file as in the form of: rose daisy lilly sunflower can anybody tell the command for this. You can find lots of IP address regular expressions on the web, see for example this StackOverflow question. The latest way to use grep is with the -E option. 14 I need to extract the characters before the character ' ('. grep -o 192.1.* zĪny line starting with 1921 will be matched, and only the matching part will be printed because of the -o switch.* matches anything up to the end of the line, including the empty string. The portion before and after the match will consistently vary. It need a way to match lines to a pattern, but only to return the portion of the line after the match. Only 1921 will be matched, and only the matching part will be printed because of the -o switch. 196 So pulling open a file with cat and then using grep to get matching lines only gets me so far when I am working with the particular log set that I am dealing with. After the string you want to match, you specify the individual files separated by a space character. Your input does not contain data where this makes any difference. 35 I have a text file that has the following format: characters (that I want to keep) (space) characters (that I want to remove) So for example: foo garbagetext hello moregarbage keepthis removethis (etc.) So I was trying to use the grep command in Linux to keep only the characters in each line up to and not including the first blank space. The name grep stands for global regular expression print. I wanted to list all the ip addresses in the file and I used grep with a pattern 192.16 but it doesnt show the whole list of IP addresses. The grep command is one of the most useful commands in a Linux terminal environment. A variation is for example, sed -n 's/UUID'\ (.\)'/\1/p'. The sed command could be written in multiple different ways. It removes the UUID bit and all double quotes and then prints whatever is left. Single quotes prevent expansion of anything between them (including backslashes) the only thing you cant do then is have single quotes in the pattern. will be matched, and only the matching part will be printed because of the -o switch. I have a file that contains many IP addresses. UUID'1ce7ffef-8faa-4138-9b92-466698762f62'. The easiest way to do that is to put single quotes around it. Only 1921 will be matched, and only the matching part will be printed because of the -o switch.
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